TA的每日心情 | 开心 2014-6-18 08:29 |
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签到天数: 14 天 [LV.3]偶尔看看II
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解决代码及点评
- <pre code_snippet_id="91880" snippet_file_name="blog_20131202_1_2646179" class="cpp" name="code"></pre><pre code_snippet_id="91880" snippet_file_name="blog_20131202_1_2646179" class="cpp" name="code"><pre code_snippet_id="91880" snippet_file_name="blog_20131202_1_2646179" class="cpp" name="code"><pre code_snippet_id="91880" snippet_file_name="blog_20131202_1_2646179" class="cpp" name="code"><pre code_snippet_id="91880" snippet_file_name="blog_20131202_1_2646179" class="cpp" name="code">/************************************************************************/
- /*10. 编程序计算下述函数在X=-7,-1,0,7时的值。 Exp log absf
-
- */
- /************************************************************************/
- #include <stdio.h>
- #include <stdlib.h>
- #include <math.h>
- double GetIt(int num)
- {
- if (num>10||num<=-7)
- {
- return exp((double)num)/(2*num);
- }
- else if (4<=num&&num<=10)
- {
- return log((double)(num+7));
- }
- else if (num==0)
- {
- return 0;
- }
- else if (-7<num&&num<4&&num!=0)
- {
- return num*fabs((double)num);
- }
-
- return 0.0;
- }
- void main()
- {
- printf("%-8lf\n",GetIt(-7));
- printf("%-8lf\n",GetIt(-1));
- printf("%-8lf\n",GetIt(0));
- printf("%-8lf\n",GetIt(7));
- system("pause");
- }
- </pre></pre></pre></pre>
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